What is the derivative of x^3-7x+6 ?

The derivative of x^3-7x+6 is 3x^2-7

What is the first derivative of x^3-7x+6 ?

The first derivative of x^3-7x+6 is 3x^2-7

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\frac{d}{d x} (x^{3} - 7 x + 6)

3 x^{2} - 7

Solution steps

\frac{d}{d x} (x^{3} - 7 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (7 x) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (6) = 0

= 3 x^{2} - 7 + 0

Simplify

= 3 x^{2} - 7

d er i v a t i v e f (x) = ln (289 sin^{2} (x))

y^{^{''''}} - 16 y = 0

\frac{d}{d t} (2 t^{\frac{4}{3}} - 3 t^{\frac{2}{3}})

\frac{d}{d x} (3 e^{x} + \frac{4}{3 x})

d er i v a t i v e e^{x} cos (2 x)

What is the derivative of x^3-7x+6 ?
The derivative of x^3-7x+6 is 3x^2-7
What is the first derivative of x^3-7x+6 ?
The first derivative of x^3-7x+6 is 3x^2-7