fläche y=6x^2,y=x^2+4

Lösung

fläche

y = 6 x^{2}, y = x^{2} + 4

\frac{32}{3 5}

Dezimale

4.77027 \dots

Schritte zur Lösung

Wenden Sie die Flächenformel an:

\int_{- \frac{2}{5}}^{\frac{2}{5}} 6 x^{2} - (x^{2} + 4) d x

Löse

\int_{- \frac{2}{5}}^{\frac{2}{5}} 6 x^{2} - (x^{2} + 4) d x : \frac{32}{3 5}

Die Fläche ist:

= \frac{32}{3 5}

\frac{d}{d x} (3 + x^{2})

\frac{\partial}{\partial y} (arctan (x))

\frac{d}{d x} (2 (x - 2 π))

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\int \frac{x ^{2} - 3 x + 8}{( x ^{2} - 4 x + 7 ) ^{2}} d x