d/(dh)(pi{r}^2h)

解答

\frac{d}{d h} (π r^{2} h)

π r^{2}

求解步骤

\frac{d}{d h} (π r^{2} h)

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= π r^{2} \frac{d h}{d h}

使用常见微分定则:

\frac{d h}{d h} = 1

= π r^{2} \cdot 1

化简

= π r^{2}

\int_{1}^{4} \frac{1}{x ( x - 5 )} d x

y^{^{'}} (x^{2} + 1) + 3 x (y - 1) = 0

\int 7 x sin (2 x) d x

x \to 2 - lim (\frac{2}{2 - x})

t \to 2 lim (ln (t^{3}))