What is the sum from n=1 to infinity of 2-3(0.8)^n ?

The sum from n=1 to infinity of 2-3(0.8)^n is diverges

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sum from n=1 to infinity of 2-3(0.8)^n

n = 1 \sum \infty 2 - 3 (0.8)^{n}

diverges

Solution steps

n = 1 \sum \infty 2 - 3 \cdot 0. 8^{n}

Apply Series Divergence Test:

diverges

= diverges

\int_{0}^{\infty} x e^{- 2 x} d x

d er i v a t i v e (x)^{4} cos (7 x - 5)

\int e^{- 5 x} sin (6 x) d x

\int 10 x - 9 d x

t an g e n t f (x) = 12 e^{- 0.6 x}, at x = 9

What is the sum from n=1 to infinity of 2-3(0.8)^n ?
The sum from n=1 to infinity of 2-3(0.8)^n is diverges