What is the derivative of f(x)=5x^3+8 ?

The derivative of f(x)=5x^3+8 is 15x^2

What is the first derivative of f(x)=5x^3+8 ?

The first derivative of f(x)=5x^3+8 is 15x^2

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derivative of

f (x) = 5 x^{3} + 8

15 x^{2}

Solution steps

\frac{d}{d x} (5 x^{3} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (8)

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (8) = 0

= 15 x^{2} + 0

Simplify

= 15 x^{2}

x \to 0 lim (\frac{- 1}{x ^{3}})

n = 1 \sum \infty \frac{1}{4 n - 1}

a re a y = x^{2}, [0, 4]

\int (\frac{2 x ^{4} + 3 x ^{2} - 6}{x ^{3}}) d x

x \to 3 - lim (\frac{x - 4}{x - 3})

What is the derivative of f(x)=5x^3+8 ?
The derivative of f(x)=5x^3+8 is 15x^2
What is the first derivative of f(x)=5x^3+8 ?
The first derivative of f(x)=5x^3+8 is 15x^2