(\partial)/(\partial x)(sin(7x^4y-7xy^4))

Lösung

\frac{\partial}{\partial x} (sin (7 x^{4} y - 7 x y^{4}))

cos (7 x^{4} y - 7 x y^{4}) (28 y x^{3} - 7 y^{4})

Schritte zur Lösung

\frac{\partial}{\partial x} (sin (7 x^{4} y - 7 x y^{4}))

Behandle

y

als Konstante

Wende die Kettenregel an:

cos (7 x^{4} y - 7 x y^{4}) \frac{\partial}{\partial x} (7 x^{4} y - 7 x y^{4})

= cos (7 x^{4} y - 7 x y^{4}) \frac{\partial}{\partial x} (7 x^{4} y - 7 x y^{4})

\frac{\partial}{\partial x} (7 x^{4} y - 7 x y^{4}) = 28 y x^{3} - 7 y^{4}

= cos (7 x^{4} y - 7 x y^{4}) (28 y x^{3} - 7 y^{4})

y^{^{''}} - 10 y^{^{'}} + 34 y = 0

\frac{\partial}{\partial x} (x^{- \frac{1}{2}} cos (x))

in v erse l a pl a ce \frac{s - 1}{s ( s ^{2} + s + 1 )}

\frac{\partial}{\partial x} (e^{e^{x y}})

d er i v a t i v e x ∣ x - 2 ∣