What is the integral from-1 to 1 of x^3-6x ?

The integral from-1 to 1 of x^3-6x is 0

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integral from-1 to 1 of x^3-6x

\int_{- 1}^{1} x^{3} - 6 x d x

0

Solution steps

\int_{- 1}^{1} x^{3} - 6 x d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{3} - 6 x :

Odd

= 0

t an g e n t x^{4} + 5 x^{2} - x

d er i v a t i v e h (w) = \frac{w ^{2} - 1}{w ^{2} + 1}

\frac{d}{d x} (\frac{x ^{3}}{12})

d er i v a t i v e \frac{1}{2} (9 t^{2} + t)^{- 3}

\int_{0}^{1} x^{2} + x d x

What is the integral from-1 to 1 of x^3-6x ?
The integral from-1 to 1 of x^3-6x is 0