What is the derivative of (2x^{1/2}) ?

The derivative of (2x^{1/2}) is 1/(2^{1/2)x^{1/2}}

What is the first derivative of (2x^{1/2}) ?

The first derivative of (2x^{1/2}) is 1/(2^{1/2)x^{1/2}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} ((2 x)^{\frac{1}{2}})

\frac{1}{2 ^{\frac{1}{2}} x ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} ((2 x)^{\frac{1}{2}})

Simplify

(2 x)^{\frac{1}{2}} : 2^{\frac{1}{2}} x^{\frac{1}{2}}

= \frac{d}{d x} (2^{\frac{1}{2}} x^{\frac{1}{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2^{\frac{1}{2}} \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2^{\frac{1}{2}} \cdot \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

2^{\frac{1}{2}} \cdot \frac{1}{2} x^{\frac{1}{2} - 1} : \frac{1}{2 ^{\frac{1}{2}} x ^{\frac{1}{2}}}

= \frac{1}{2 ^{\frac{1}{2}} x ^{\frac{1}{2}}}

\frac{d}{d x} (cos (x^{2} e^{x}))

x \to - 2 lim (- x^{2} + 5 x - 1)

in v erse l a pl a ce F (s) = \frac{s ^{2} - 2 s - 6}{s - 2}

x \to 3 + lim (\frac{x + 2}{x - 2})

\frac{d}{d x} (x^{l n (x)})

What is the derivative of (2x^{1/2}) ?
The derivative of (2x^{1/2}) is 1/(2^{1/2)x^{1/2}}
What is the first derivative of (2x^{1/2}) ?
The first derivative of (2x^{1/2}) is 1/(2^{1/2)x^{1/2}}