What is the derivative of x^{(-2/5}) ?

The derivative of x^{(-2/5}) is -2/(5x^{7/5)}

What is the first derivative of x^{(-2/5}) ?

The first derivative of x^{(-2/5}) is -2/(5x^{7/5)}

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\frac{d}{d x} (x^{\frac{- 2}{5}})

- \frac{2}{5 x ^{\frac{7}{5}}}

Solution steps

\frac{d}{d x} (x^{\frac{- 2}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{- 2}{5} x^{\frac{- 2}{5} - 1}

Simplify

\frac{- 2}{5} x^{\frac{- 2}{5} - 1} : - \frac{2}{5 x ^{\frac{7}{5}}}

= - \frac{2}{5 x ^{\frac{7}{5}}}

f (x) = 2 x cos (x^{2})

\int_{0}^{2} \frac{7}{x - 2} d x

k = 1 \sum \infty ln (k)

t an g e n t f (x) = arcsin (3 x), at x = \frac{1}{6}

\int 1 + (2 x - \frac{1}{8 x})^{2} d x

What is the derivative of x^{(-2/5}) ?
The derivative of x^{(-2/5}) is -2/(5x^{7/5)}
What is the first derivative of x^{(-2/5}) ?
The first derivative of x^{(-2/5}) is -2/(5x^{7/5)}