(x^2-4)((dy)/(dx))+4y=(x+2)^2

解答

(x^{2} - 4) (\frac{d y}{d x}) + 4 y = (x + 2)^{2}

y = \frac{x ( x + 2 )}{x - 2} + \frac{c _{1} ( x + 2 )}{x - 2}

求解步骤

(x^{2} - 4) (\frac{d y}{d x}) + 4 y = (x + 2)^{2}

求解线性方程:

y = \frac{x ( x + 2 )}{x - 2} + \frac{c _{1} ( x + 2 )}{x - 2}

y = \frac{x ( x + 2 )}{x - 2} + \frac{c _{1} ( x + 2 )}{x - 2}

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