derivative of ln((x^2-1^3))

解答

\frac{d}{d x} (ln ((x^{2} - 1)^{3}))

\frac{6 x}{x ^{2} - 1}

求解步骤

\frac{d}{d x} (ln ((x^{2} - 1)^{3}))

使用连锁律:

\frac{1}{( x ^{2} - 1 ) ^{3}} \frac{d}{d x} ((x^{2} - 1)^{3})

= \frac{1}{( x ^{2} - 1 ) ^{3}} \frac{d}{d x} ((x^{2} - 1)^{3})

\frac{d}{d x} ((x^{2} - 1)^{3}) = 6 x (x^{2} - 1)^{2}

= \frac{1}{( x ^{2} - 1 ) ^{3}} \cdot 6 x (x^{2} - 1)^{2}

化简

\frac{1}{( x ^{2} - 1 ) ^{3}} \cdot 6 x (x^{2} - 1)^{2} : \frac{6 x}{x ^{2} - 1}

= \frac{6 x}{x ^{2} - 1}

\frac{\partial}{\partial x} (- x sin (y))

in v erse l a pl a ce \frac{1}{s ( s ^{2} + 0.2 s + 1 )}

\frac{d}{d x} ((25 - x^{2})^{\frac{1}{2}})

f (x) = \frac{1}{2 x ^{6}}

n = 1 \sum \infty cos^{2} (n)