What is the integral of (5x^{14}-2x^5) ?

The integral of (5x^{14}-2x^5) is (x^{15})/3-(x^6)/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (5x^{14}-2x^5)

\int (5 x^{14} - 2 x^{5}) d x

\frac{x ^{15}}{3} - \frac{x ^{6}}{3} + C

Solution steps

\int 5 x^{14} - 2 x^{5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{14} d x - \int 2 x^{5} d x

\int 5 x^{14} d x = \frac{x ^{15}}{3}

\int 2 x^{5} d x = \frac{x ^{6}}{3}

= \frac{x ^{15}}{3} - \frac{x ^{6}}{3}

Add a constant to the solution

= \frac{x ^{15}}{3} - \frac{x ^{6}}{3} + C

\int (y^{2} - 1)^{2} d y

\frac{d}{d x} (x^{2} + a^{2})

\int e^{3 x - 4} d x

\frac{\partial}{\partial x} (e^{x e^{y}})

f^{^{'}} (x) = 7 e^{- e} - 5 e^{- 7 x}

What is the integral of (5x^{14}-2x^5) ?
The integral of (5x^{14}-2x^5) is (x^{15})/3-(x^6)/3+C