What is area 2x+1,x^2-4x ?

The answer to area 2x+1,x^2-4x is -(74sqrt(10))/3+38sqrt(10)

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area 2x+1,x^2-4x

area

2 x + 1, x^{2} - 4 x

- \frac{74 10}{3} + 3810

Decimal

42.16370 \dots

Solution steps

Apply the area formula:

\int_{3 - 10}^{3 + 10} 2 x + 1 - (x^{2} - 4 x) d x

Solve

\int_{3 - 10}^{3 + 10} 2 x + 1 - (x^{2} - 4 x) d x : - \frac{74 10}{3} + 3810

The area is:

= - \frac{74 10}{3} + 3810

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{5 + e ^{x}})

f (x) = (x^{3} - 2 x^{2} + 3 x + 1)^{11}

\frac{d}{d x} (x - 1 - x^{2})

y^{^{''}} + 4 y^{^{'}} + 8 y = 0

\int \frac{5}{x ( x ^{4} + 6 )} d x

What is area 2x+1,x^2-4x ?
The answer to area 2x+1,x^2-4x is -(74sqrt(10))/3+38sqrt(10)