What is the tangent of x^2+y^2=100,(6,8) ?

The tangent of x^2+y^2=100,(6,8) is y=-3/4 x+25/2

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tangent of x^2+y^2=100,(6,8)

tangent of

x^{2} + y^{2} = 100, (6, 8)

y = - \frac{3}{4} x + \frac{25}{2}

Solution steps

Find the slope of

x^{2} + y^{2} = 100 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(6, 8) : y = - \frac{3}{4} x + \frac{25}{2}

y = - \frac{3}{4} x + \frac{25}{2}

t an g e n t y = x^{2}, (- 0.6, 0.36)

\int - ln ∣ cos (x) ∣ d x

\frac{d}{d x} (3 \frac{1}{x})

\int cos (20 x) cos (13 x) d x

d er i v a t i v e y = - 1.97 x^{2} + 0.51 x + 8.1

What is the tangent of x^2+y^2=100,(6,8) ?
The tangent of x^2+y^2=100,(6,8) is y=-3/4 x+25/2