What is the tangent of f(x)= 7/(4-x),\at x=-1 ?

The tangent of f(x)= 7/(4-x),\at x=-1 is y= 7/25 x+42/25

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tangent of f(x)= 7/(4-x),\at x=-1

tangent of

f (x) = \frac{7}{4 - x}, at x = - 1

y = \frac{7}{25} x + \frac{42}{25}

Solution steps

Find the tangent point:

(- 1, \frac{7}{5})

Find the slope of

f (x) = \frac{7}{4 - x} : \frac{df ( x )}{d x} = \frac{7}{( 4 - x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{25}

Find the line with slope m=

\frac{7}{25}

and passing through

(- 1, \frac{7}{5}) : y = \frac{7}{25} x + \frac{42}{25}

y = \frac{7}{25} x + \frac{42}{25}

\frac{\partial}{\partial x} (y^{4} sin (2 x))

\int 24 y (1 - x - y) d y

\frac{d}{d x} (\frac{( 3 x + 1 )}{x ^{\frac{2}{3}}})

in v erse l a pl a ce e^{- 2 s} (\frac{1}{s + 1})

\int t e^{- 2 t} d t

What is the tangent of f(x)= 7/(4-x),\at x=-1 ?
The tangent of f(x)= 7/(4-x),\at x=-1 is y= 7/25 x+42/25