y^{''}-2y^'+y=0

Lösung

y^{^{''}} - 2 y^{^{'}} + y = 0

y = c_{1} e^{t} + c_{2} t e^{t}

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} t e^{t}

y = c_{1} e^{t} + c_{2} t e^{t}

\int x (12 x + 4) d x

x \to 2 lim (ln ∣ 2 - x ∣)

t an g e n t f (x) = - x^{3} + 9 x^{2} - 6 x + 9, at x = 7

x \to - \infty lim (\frac{x}{c})

\int 2 (2 x + 8)^{5} d x