derivative of sin(2x^3+x^2+1)

Lösung

\frac{d}{d x} (sin (2 x^{3} + x^{2} + 1))

cos (2 x^{3} + x^{2} + 1) (6 x^{2} + 2 x)

Schritte zur Lösung

\frac{d}{d x} (sin (2 x^{3} + x^{2} + 1))

Wende die Kettenregel an:

cos (2 x^{3} + x^{2} + 1) \frac{d}{d x} (2 x^{3} + x^{2} + 1)

= cos (2 x^{3} + x^{2} + 1) \frac{d}{d x} (2 x^{3} + x^{2} + 1)

\frac{d}{d x} (2 x^{3} + x^{2} + 1) = 6 x^{2} + 2 x

= cos (2 x^{3} + x^{2} + 1) (6 x^{2} + 2 x)

x \to 0 lim (\frac{a x - a ln ( x + 1 )}{x ln ( x + 1 )})

\int_{2}^{10} \frac{1}{x} d x

\frac{d}{d x} (x e^{(2 x)})

\frac{\partial}{\partial x} (9 x^{2} + y^{2})

n = 1 \sum \infty \frac{n + 5}{5 ^{n}}