(x)(dy)/(dx)+y= 1/(y^2)

解答

(x) \frac{d y}{d x} + y = \frac{1}{y ^{2}}

y = \frac{3 - c _{1} + x ^{3}}{x}

求解步骤

(x) \frac{d y}{d x} + y = \frac{1}{y ^{2}}

求解可分离方程:

y = \frac{3 - c _{1} + x ^{3}}{x}

y = \frac{3 - c _{1} + x ^{3}}{x}

d er i v a t i v e \frac{x ^{2} - 9 x + 20}{( x + 2 ) ( x - 2 )}

\int 20 x^{\frac{3}{2}} d x

in v erse l a pl a ce \frac{2}{2 s - 1}

\frac{d}{d x} (5^{- \frac{x}{2}})

d er i v a t i v e 2 \cdot x