What is area x^2+4,-x^2-1,-2,3 ?

The answer to area x^2+4,-x^2-1,-2,3 is 145/3

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area x^2+4,-x^2-1,-2,3

area

x^{2} + 4, - x^{2} - 1, - 2, 3

\frac{145}{3}

Decimal

48.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{2} + 4 - (- x^{2} - 1) d x

Solve

\int_{- 2}^{3} x^{2} + 4 - (- x^{2} - 1) d x : \frac{145}{3}

The area is:

= \frac{145}{3}

\frac{\partial}{\partial x} (cos (- t + y + e^{x}))

\frac{d}{d x} (ln (cos (ln (x))))

\frac{d y}{d t} = 3 t e^{- y}

d er i v a t i v e y = x arcsin (2 x)

\frac{\partial}{\partial x} (3 x^{3} y - \frac{4}{x} + 2 y^{\frac{1}{2}})