What is the tangent of f(x)= 6/(x^2),\at x=1 ?

The tangent of f(x)= 6/(x^2),\at x=1 is y=-12x+18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)= 6/(x^2),\at x=1

tangent of

f (x) = \frac{6}{x ^{2}}, at x = 1

y = - 12 x + 18

Solution steps

Find the tangent point:

(1, 6)

Find the slope of

f (x) = \frac{6}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{12}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 12

Find the line with slope m=

- 12

and passing through

(1, 6) : y = - 12 x + 18

y = - 12 x + 18

y^{^{''}} - 3 y^{^{'}} - 10 y = 0

t a y l or \frac{1}{( 1 + x ) ^{2}}, 1

\frac{d}{d x} (5 x)

\int 4 x^{2} + 1 d x

\frac{\partial}{\partial x} (x^{2} - 4 x y + y^{2} + 6 y + 3)

What is the tangent of f(x)= 6/(x^2),\at x=1 ?
The tangent of f(x)= 6/(x^2),\at x=1 is y=-12x+18