What is the derivative of x^2+2xy ?

The derivative of x^2+2xy is 2x+2(y+x(dy)/(dx))

What is the first derivative of x^2+2xy ?

The first derivative of x^2+2xy is 2x+2(y+x(dy)/(dx))

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\frac{d}{d x} (x^{2} + 2 x y)

2 x + 2 (y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (x^{2} + 2 x y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x y)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x y) = 2 (y + x \frac{d y}{d x})

= 2 x + 2 (y + x \frac{d y}{d x})

n = 0 \sum \infty (\frac{e}{4 π})^{n}

\int \frac{x ^{2} + 5 x + 4}{x ^{2} - 2 x + 1} d x

\frac{d}{d x} (tan (sec (cos (x))))

s l o p e y^{4} - 4 y^{2} = x^{4} - 9 x^{2}, (- 3, 2)

d er i v a t i v e (\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) (y + 5 y^{3})

What is the derivative of x^2+2xy ?
The derivative of x^2+2xy is 2x+2(y+x(dy)/(dx))
What is the first derivative of x^2+2xy ?
The first derivative of x^2+2xy is 2x+2(y+x(dy)/(dx))