What is the tangent of f(x)=sqrt(5x+4),\at x=1 ?

The tangent of f(x)=sqrt(5x+4),\at x=1 is y= 5/6 x+13/6

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tangent of f(x)=sqrt(5x+4),\at x=1

tangent of

f (x) = 5 x + 4, at x = 1

y = \frac{5}{6} x + \frac{13}{6}

Solution steps

Find the tangent point:

(1, 3)

Find the slope of

f (x) = 5 x + 4 : \frac{df ( x )}{d x} = \frac{5}{2 5 x + 4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{6}

Find the line with slope m=

\frac{5}{6}

and passing through

(1, 3) : y = \frac{5}{6} x + \frac{13}{6}

y = \frac{5}{6} x + \frac{13}{6}

\frac{d}{d x} (arctan (x) + arccos (x))

x \to \infty lim (4 x + 5)

t an g e n t f (x) = \frac{2}{x}, at x = 2

n = 1 \sum \infty (\frac{2}{n})^{n} \cdot n!

\frac{\partial}{\partial x} (e^{x} ln (y))

What is the tangent of f(x)=sqrt(5x+4),\at x=1 ?
The tangent of f(x)=sqrt(5x+4),\at x=1 is y= 5/6 x+13/6