y^'=((3x^2-e^x))/((2y-5))

解

y^{^{'}} = \frac{( 3 x ^{2} - e ^{x} )}{( 2 y - 5 )}

y = \frac{5 + 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}, y = \frac{5 - 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}

解答ステップ

y^{'} (x) = \frac{( 3 x ^{2} - e ^{x} )}{( 2 y - 5 )}

分離可能 ODE を解く:

y = \frac{5 + 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}, y = \frac{5 - 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}

y = \frac{5 + 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}, y = \frac{5 - 25 - 4 ( - c _{1} + e ^{x} - x ^{3} )}{2}