(\partial)/(\partial y)(2xln(y)-yz)

Lösung

\frac{\partial}{\partial y} (2 x ln (y) - yz)

\frac{2 x}{y} - z

Schritte zur Lösung

\frac{\partial}{\partial y} (2 x ln (y) - yz)

Behandle

x, z

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x ln (y)) - \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (2 x ln (y)) = \frac{2 x}{y}

\frac{\partial}{\partial y} (yz) = z

= \frac{2 x}{y} - z

s im pl i f y (e^{- x} - e^{5}) (e^{x} + e^{- 2})

y^{^{''}} - 2 y + y = t + 1, y (0) = 0, y^{^{'}} (0) = 0

f (x) = - \frac{2}{x}

\frac{d}{d x} (x - 3 x)

\frac{\partial}{\partial x} (4 x e^{4 x y})