(\partial)/(\partial x)(x^{2y}+4y)

解答

\frac{\partial}{\partial x} (x^{2 y} + 4 y)

2 y x^{2 y - 1}

求解步骤

\frac{\partial}{\partial x} (x^{2 y} + 4 y)

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2 y}) + \frac{\partial}{\partial x} (4 y)

\frac{\partial}{\partial x} (x^{2 y}) = 2 y x^{2 y - 1}

\frac{\partial}{\partial x} (4 y) = 0

= 2 y x^{2 y - 1} + 0

化简

= 2 y x^{2 y - 1}

\int (cot^{2} (x) + cot^{4} (x)) d x

\frac{d}{d x} (ln (\frac{x + 2}{x - 2}))

t an g e n t f (x) = 5 x, at x = 5

\int tan (5 x) sec^{2} (5 x) d x

a re a x - 2, x, [0, 4]