(dy}{dx}=\frac{(x-2))/x

Lösung

\frac{d y}{d x} = \frac{( x - 2 )}{x}

y = x - 2 ln (x) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{( x - 2 )}{x}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{( x - 2 )}{x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{x - 2}{x} d x

\int \frac{x - 2}{x} d x = x - 2 ln (x) + c_{1}

y = x - 2 ln (x) + c_{1}

d er i v a t i v e (2 x^{2} + x + 1)^{- 3}

\frac{d y}{d t} = \frac{( 2 y ^{4} + t ^{4} )}{t y ^{3}}

\frac{d y}{d t} + 20 \frac{6}{5} - \frac{6}{5} e^{- 20 t} = 24

\int \frac{tan ^{2} ( x )}{sec ( x )} d x

x \to 0 lim (\frac{e ^{9 x} - 1}{x})