derivative 35+35sin((-2pit-pi)/2)

Lösung

ableitung von

35 + 35 sin (\frac{- 2 π t - π}{2})

- 35 π cos (\frac{- 2 π t - π}{2})

Schritte zur Lösung

\frac{d}{d t} (35 + 35 sin (\frac{- 2 π t - π}{2}))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (35) + \frac{d}{d t} (35 sin (\frac{- 2 π t - π}{2}))

\frac{d}{d t} (35) = 0

\frac{d}{d t} (35 sin (\frac{- 2 π t - π}{2})) = - 35 π cos (\frac{- 2 π t - π}{2})

= 0 - 35 π cos (\frac{- 2 π t - π}{2})

Vereinfache

= - 35 π cos (\frac{- 2 π t - π}{2})

\frac{d}{d x} (\frac{16}{( 2 x + 1 ) ^{3}})

\frac{\partial}{\partial x} (4 x - 4 x^{3})

\int (\frac{1}{( x - 1 ) ^{2}}) d x

h \to 0 lim (\frac{( ( 4 + h ) - 4 )}{h})

\frac{d}{d x} (a x e^{4 x})