derivative of e^{tan(2x+1})

Lösung

\frac{d}{d x} (e^{t a n (2 x + 1)})

e^{t a n (2 x + 1)} sec^{2} (2 x + 1) \cdot 2

Schritte zur Lösung

\frac{d}{d x} (e^{t a n (2 x + 1)})

Wende die Kettenregel an:

e^{t a n (2 x + 1)} \frac{d}{d x} (tan (2 x + 1))

= e^{t a n (2 x + 1)} \frac{d}{d x} (tan (2 x + 1))

\frac{d}{d x} (tan (2 x + 1)) = sec^{2} (2 x + 1) \cdot 2

= e^{t a n (2 x + 1)} sec^{2} (2 x + 1) \cdot 2

x \to 5 - lim (∣ x - 5 ∣)

\int - cos (x) + sin (x) + 2 d x

\frac{d}{d x} (- 5 x + 5)

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x + 1})

y^{^{''}} + 2 y^{^{'}} + y = \frac{- 18.5 e ^{- t}}{t ^{2} + 1}