y^'=-2xtan(y)

解答

y^{^{'}} = - 2 x tan (y)

y = arcsin (e^{- x^{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}}) + 2 πn

求解步骤

y^{'} (x) = - 2 x tan (y)

求解可分离方程:

y = arcsin (e^{- x^{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}}) + 2 πn

y = arcsin (e^{- x^{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}}) + 2 πn

s l o p e (5, - 2), (7, 10)

a re a y = 3 x, x = 8 - y^{2}

\frac{d}{d x} (15)

\int (2 cos (x) - 3 sin (x) + x) d x

d er i v a t i v e f (x) = (6 x + 7) (7 x - 8)