y^{''}-y^'=1

Lösung

y^{^{''}} - y^{^{'}} = 1

y = c_{1} e^{t} + c_{2} - t

Schritte zur Lösung

y^{''} (t) - y^{'} (t) = 1

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - t

y = c_{1} e^{t} + c_{2} - t

\int \frac{4 ^{x} + 1 0 ^{x}}{2 ^{x}} d x

\int \frac{1}{x ( 1 + x )} d x

\int \frac{x}{2} (x - 1)^{2} d x

\frac{d}{d x} (cos^{3} (x^{2} - 1))

x \to + 0 + lim (x^{\frac{2}{x}})