(x-3)(dy)/(dx)=4(x-3)^4+y

Lösung

(x - 3) \frac{d y}{d x} = 4 (x - 3)^{4} + y

y = \frac{4 x ^{4}}{3} - 16 x^{3} + 72 x^{2} - 108 x + c_{1} x - 3 c_{1}

Schritte zur Lösung

(x - 3) \frac{d y}{d x} = 4 (x - 3)^{4} + y

Solve linear ODE:

y = \frac{4 x ^{4}}{3} - 16 x^{3} + 72 x^{2} - 108 x + c_{1} x - 3 c_{1}

y = \frac{4 x ^{4}}{3} - 16 x^{3} + 72 x^{2} - 108 x + c_{1} x - 3 c_{1}

\frac{\partial}{\partial y} (e^{y x^{2}})

\int \frac{70}{( x + 1 ) ( x ^{2} + 9 ) ^{2}} d x

x \to 1 + lim (\frac{x + 7}{x + 2})

d er i v a t i v e x - ln (x)

im pl i c i t \frac{d y}{d x}, y = 2 x