integral of (5cos(x)+9sin(x))

解答

\int (5 cos (x) + 9 sin (x)) d x

5 sin (x) - 9 cos (x) + C

求解步骤

\int 5 cos (x) + 9 sin (x) d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 cos (x) d x + \int 9 sin (x) d x

\int 5 cos (x) d x = 5 sin (x)

\int 9 sin (x) d x = - 9 cos (x)

= 5 sin (x) - 9 cos (x)

解答补常数

= 5 sin (x) - 9 cos (x) + C

\int \frac{7 + x + x}{x} d x

\int_{- 1}^{2} \frac{∣ x ∣}{x} d x

t an g e n t f (x) = (4 x + 2)^{\frac{1}{4}}, at x = 1

\frac{\partial}{\partial x} (\frac{4}{4 x + y})

n = 1 \sum \infty \frac{2 n}{3}