2y^'+4y=2te^{-2t}

Lösung

2 y^{^{'}} + 4 y = 2 t e^{- 2 t}

y = \frac{t ^{2}}{2 e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

Schritte zur Lösung

2 y^{'} (t) + 4 y = 2 t e^{- 2 t}

Solve linear ODE:

y = \frac{t ^{2}}{2 e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

y = \frac{t ^{2}}{2 e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

\int \frac{3 - x}{3 + x} d x

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