What is the solution for (dy)/(dx)+y/(100+x)=4 ?

The solution for (dy)/(dx)+y/(100+x)=4 is y=(2(x^2+200x))/(100+x)+(c_{1})/(100+x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)+y/(100+x)=4

\frac{d y}{d x} + \frac{y}{100 + x} = 4

y = \frac{2 ( x ^{2} + 200 x )}{100 + x} + \frac{c _{1}}{100 + x}

Solution steps

\frac{d y}{d x} + \frac{y}{100 + x} = 4

Solve linear ODE:

y = \frac{2 ( x ^{2} + 200 x )}{100 + x} + \frac{c _{1}}{100 + x}

y = \frac{2 ( x ^{2} + 200 x )}{100 + x} + \frac{c _{1}}{100 + x}

\int - \frac{3 x - 1}{( x - 5 ) ( x - 7 ) ^{2}} d x

\int_{0}^{2 π} cos^{3} (x) d x

y^{^{''}} - 2 y^{^{'}} = x

\frac{d}{d x} (\frac{9}{2 x + 1})

\int_{1 - 3 x}^{1} \frac{u ^{3}}{1 + u ^{2}} d u

What is the solution for (dy)/(dx)+y/(100+x)=4 ?
The solution for (dy)/(dx)+y/(100+x)=4 is y=(2(x^2+200x))/(100+x)+(c_{1})/(100+x)