What is the integral from-1 to 1 of x^7(1+x^8)^7 ?

The integral from-1 to 1 of x^7(1+x^8)^7 is 0

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integral from-1 to 1 of x^7(1+x^8)^7

\int_{- 1}^{1} x^{7} (1 + x^{8})^{7} d x

0

Solution steps

\int_{- 1}^{1} x^{7} (1 + x^{8})^{7} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{7} (1 + x^{8})^{7} :

Odd

= 0

d er i v a t i v e f (x) = \frac{13 - x ^{4}}{3}

\int sec^{2} (x) + 6 d x

in v erse l a pl a ce \frac{( e ^{- 4 s} )}{( s + 2 ) ^{3}}

\frac{\partial}{\partial x} ((x - 3)^{2} + (y - 2)^{2})

in v erse l a pl a ce {\frac{1}{s ^{4} - 9}}

What is the integral from-1 to 1 of x^7(1+x^8)^7 ?
The integral from-1 to 1 of x^7(1+x^8)^7 is 0