What is the solution for x(dy)/(dx)=y+2xe^{-y/x} ?

The solution for x(dy)/(dx)=y+2xe^{-y/x} is y=ln(2ln(x)+c_{1})x

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x(dy)/(dx)=y+2xe^{-y/x}

x \frac{d y}{d x} = y + 2 x e^{- \frac{y}{x}}

y = ln (2 ln (x) + c_{1}) x

Solution steps

x \frac{d y}{d x} = y + 2 x e^{- \frac{y}{x}}

Solve using substitution:

y = ln (2 ln (x) + c_{1}) x

y = ln (2 ln (x) + c_{1}) x

\frac{d y}{d x} = x - 2.5 y

ma c l a u r in 1.5 (1 + e^{- 0.2 t})

x \to 0 lim ((1 - 4 x)^{\frac{6}{x}})

f (x) = 2 cos (3 x) + 3 e^{- 0.25 x}

(x, y) \to (0, 0) lim (0)

What is the solution for x(dy)/(dx)=y+2xe^{-y/x} ?
The solution for x(dy)/(dx)=y+2xe^{-y/x} is y=ln(2ln(x)+c_{1})x