(\partial)/(\partial x)(-7x^2+7y^2-7)

解答

\frac{\partial}{\partial x} (- 7 x^{2} + 7 y^{2} - 7)

- 14 x

求解步骤

\frac{\partial}{\partial x} (- 7 x^{2} + 7 y^{2} - 7)

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (7 x^{2}) + \frac{\partial}{\partial x} (7 y^{2}) - \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (7 x^{2}) = 14 x

\frac{\partial}{\partial x} (7 y^{2}) = 0

\frac{\partial}{\partial x} (7) = 0

= - 14 x + 0 - 0

化简

= - 14 x

\frac{\partial}{\partial y} (\frac{x + y}{1 + y ^{2}})

\frac{d}{d x} (- e^{- 5 x})

d er i v a t i v e (2 + x^{2}) \frac{2 - x ^{2}}{2 - x}

d er i v a t i v e 9 x^{8} + 1

\int_{0}^{1} \frac{1}{2 x - 1} d x