What is the integral of \sqrt[6]{2}+\sqrt[6]{x} ?

The integral of \sqrt[6]{2}+\sqrt[6]{x} is \sqrt[6]{2}x+6/7 x^{7/6}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of \sqrt[6]{2}+\sqrt[6]{x}

\int 62 + 6 x d x

62 x + \frac{6}{7} x^{\frac{7}{6}} + C

Solution steps

\int 62 + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 62 d x + \int 6 x d x

\int 62 d x = 62 x

\int 6 x d x = \frac{6}{7} x^{\frac{7}{6}}

= 62 x + \frac{6}{7} x^{\frac{7}{6}}

Add a constant to the solution

= 62 x + \frac{6}{7} x^{\frac{7}{6}} + C

y^{^{''}} - y = 9 e^{5 t} + 6 t e^{5 t} + 3 t^{2} e^{5 t}

x \to 0 lim (3 3 x)

\frac{d}{d x} (x^{2} + \frac{2}{x})

\int \frac{3 - e ^{x}}{e ^{5 x}} d x

\int 3 - \frac{4}{2 x + 1} d x

What is the integral of \sqrt[6]{2}+\sqrt[6]{x} ?
The integral of \sqrt[6]{2}+\sqrt[6]{x} is \sqrt[6]{2}x+6/7 x^{7/6}+C