integral of ln(1-sqrt(x))

Lösung

\int ln (1 - x) d x

x ln (1 - x) - \frac{1}{2} x - x - ln - x + 1 - \frac{1}{2} + 2 + C

Schritte zur Lösung

\int ln (1 - x) d x

Wende die partielle Integration an

= x ln (1 - x) - \int - \frac{x}{2 ( 1 - x )} d x

\int - \frac{x}{2 ( 1 - x )} d x = \frac{1}{2} (1 - x)^{2} - 2 (1 - x) + ln 1 - x

= x ln (1 - x) - (\frac{1}{2} (1 - x)^{2} - 2 (1 - x) + ln 1 - x)

Vereinfache

x ln (1 - x) - (\frac{1}{2} (1 - x)^{2} - 2 (1 - x) + ln 1 - x) : x ln (1 - x) - \frac{1}{2} x - x - ln - x + 1 - \frac{1}{2} + 2

= x ln (1 - x) - \frac{1}{2} x - x - ln - x + 1 - \frac{1}{2} + 2

Füge eine Konstante zur Lösung hinzu

= x ln (1 - x) - \frac{1}{2} x - x - ln - x + 1 - \frac{1}{2} + 2 + C

\int \frac{4 x ^{2}}{( 16 + x ^{2} ) ^{2}} d x

y^{^{''}} - 6 y^{^{'}} - 7 y = 15 e^{2 t}

\int - \frac{5}{x ^{2}} d x

d er i v a t i v e \frac{4 4 q}{1 - q}

\frac{d y}{d x} + y = 2 x