What is the d/(dt)(sqrt(20-25sin^2(t))) ?

The d/(dt)(sqrt(20-25sin^2(t))) is -(25sin(2t))/(2sqrt(20-25sin^2(t)))

What is the first d/(dt)(sqrt(20-25sin^2(t))) ?

The first d/(dt)(sqrt(20-25sin^2(t))) is -(25sin(2t))/(2sqrt(20-25sin^2(t)))

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العربية

\frac{d}{d t} (20 - 25 sin^{2} (t))

- \frac{25 sin ( 2 t )}{2 20 - 25 sin ^{2} ( t )}

Solution steps

\frac{d}{d t} (20 - 25 sin^{2} (t))

Apply the chain rule:

\frac{1}{2 20 - 25 sin ^{2} ( t )} \frac{d}{d t} (20 - 25 sin^{2} (t))

= \frac{1}{2 20 - 25 sin ^{2} ( t )} \frac{d}{d t} (20 - 25 sin^{2} (t))

\frac{d}{d t} (20 - 25 sin^{2} (t)) = - 25 sin (2 t)

= \frac{1}{2 20 - 25 sin ^{2} ( t )} (- 25 sin (2 t))

Simplify

\frac{1}{2 20 - 25 sin ^{2} ( t )} (- 25 sin (2 t)) : - \frac{25 sin ( 2 t )}{2 20 - 25 sin ^{2} ( t )}

= - \frac{25 sin ( 2 t )}{2 20 - 25 sin ^{2} ( t )}

\int 3 sin (x) d x

\frac{\partial}{\partial x} (x^{y} + ln (z))

sec (x) \frac{d y}{d x} = e^{y + s i n (x)}

\int \frac{x}{x ^{2} + 7} d x

\frac{\partial}{\partial x} (- 4 x^{2})

What is the d/(dt)(sqrt(20-25sin^2(t))) ?
The d/(dt)(sqrt(20-25sin^2(t))) is -(25sin(2t))/(2sqrt(20-25sin^2(t)))
What is the first d/(dt)(sqrt(20-25sin^2(t))) ?
The first d/(dt)(sqrt(20-25sin^2(t))) is -(25sin(2t))/(2sqrt(20-25sin^2(t)))