What is (\partial)/(\partial x)(2x^2+2y-8) ?

The answer to (\partial)/(\partial x)(2x^2+2y-8) is 4x

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(\partial)/(\partial x)(2x^2+2y-8)

\frac{\partial}{\partial x} (2 x^{2} + 2 y - 8)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 2 y - 8)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (8)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (8) = 0

= 4 x + 0 - 0

Simplify

= 4 x

t an g e n t f (x) = 5 x + 6, (2, 4)

\frac{d}{d x} (sin (2 x) + 3 ln (e) + 4 x)

s l o p e (4, 2), (3, - 1)

\frac{\partial}{\partial θ} (cos^{2} (θ))

\int (cos (θ))^{3} d θ

What is (\partial)/(\partial x)(2x^2+2y-8) ?
The answer to (\partial)/(\partial x)(2x^2+2y-8) is 4x