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Popular Calculus >

area y=4sqrt(x),y=2x

Solution

area

y = 4 x, y = 2 x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 4 x - 2 x d x

Solve

\int_{0}^{4} 4 x - 2 x d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Graph

Popular Examples

tangent of y=sqrt(2x+1)

t an g e n t y = 2 x + 1

inverse oflaplace 1/((s^2+1)(s^2+25))

in v erse l a pl a ce \frac{1}{( s ^{2} + 1 ) ( s ^{2} + 25 )}

y^'=((5x^3+y^3))/(xy^2)

y^{^{'}} = \frac{( 5 x ^{3} + y ^{3} )}{x y ^{2}}

derivative of f(x)=sqrt(6x+1)

d er i v a t i v e f (x) = 6 x + 1

derivative of r(x)=sin(x^2)+(1-x)/(1+x)

d er i v a t i v e r (x) = sin (x^{2}) + \frac{1 - x}{1 + x}

Frequently Asked Questions (FAQ)

What is area y=4sqrt(x),y=2x ?
The answer to area y=4sqrt(x),y=2x is 16/3