What is (\partial)/(\partial y)(2y+1) ?

The answer to (\partial)/(\partial y)(2y+1) is 2

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(\partial)/(\partial y)(2y+1)

\frac{\partial}{\partial y} (2 y + 1)

2

Solution steps

\frac{\partial}{\partial y} (2 y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (1) = 0

= 2 + 0

Simplify

= 2

d er i v a t i v e (t + 1)^{3} t^{2} + 84

d er i v a t i v e x^{2} arctan (2 x)

t a y l or e^{x - 1}, 1

d er i v a t i v e f (x) = \frac{4 x ^{2}}{( x ^{2} + x ) ^{3}}

\frac{\partial}{\partial x} (π (\frac{x}{2})^{2} h)

What is (\partial)/(\partial y)(2y+1) ?
The answer to (\partial)/(\partial y)(2y+1) is 2