What is (\partial)/(\partial y)(2xy^2-3) ?

The answer to (\partial)/(\partial y)(2xy^2-3) is 4xy

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(\partial)/(\partial y)(2xy^2-3)

\frac{\partial}{\partial y} (2 x y^{2} - 3)

4 x y

Solution steps

\frac{\partial}{\partial y} (2 x y^{2} - 3)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y^{2}) - \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (2 x y^{2}) = 4 x y

\frac{\partial}{\partial y} (3) = 0

= 4 x y - 0

Simplify

= 4 x y

x \to 1 lim (\frac{x + 4}{x + 2})

\frac{d}{d x} (4 + 3 x)

x \to \infty lim (1 - 2 x)

\frac{d}{d x} (e^{x} x + e^{x})

\frac{d y}{d x} = \frac{( 3 x ^{2} + 4 x - 4 )}{2 y - 4}

What is (\partial)/(\partial y)(2xy^2-3) ?
The answer to (\partial)/(\partial y)(2xy^2-3) is 4xy