limit as h approaches 0 of (4^h-1)/h

Lösung

h \to 0 lim (\frac{4 ^{h} - 1}{h})

2 ln (2)

Dezimale

1.38629 \dots

Schritte zur Lösung

h \to 0 lim (\frac{4 ^{h} - 1}{h})

Wende das L'Hopital Theorem an

= h \to 0 lim (\frac{ln ( 2 ) \cdot 2 ^{2 h + 1}}{1})

Setze den Wert

h = 0

ein

= \frac{ln ( 2 ) \cdot 2 ^{2 \cdot 0 + 1}}{1}

Vereinfache

= 2 ln (2)

\int \frac{e ^{x}}{x} d x

d er i v a t i v e \frac{8 x + 1}{x}

t an g e n t f (x) = x^{2} - 2 x + 1, at x = - 1

a re a f (x) = 3 + 2 x - x^{2}, g (x) = x^{2} - 4 x + 3

a re a y = x, y = \frac{1}{4} x, x = 25