derivative of ln((x+1/(x-1)))

Lösung

\frac{d}{d x} (ln (\frac{x + 1}{x - 1}))

- \frac{2}{( x + 1 ) ( x - 1 )}

Schritte zur Lösung

\frac{d}{d x} (ln (\frac{x + 1}{x - 1}))

Wende die Kettenregel an:

\frac{1}{\frac{x + 1}{x - 1}} \frac{d}{d x} (\frac{x + 1}{x - 1})

= \frac{1}{\frac{x + 1}{x - 1}} \frac{d}{d x} (\frac{x + 1}{x - 1})

\frac{d}{d x} (\frac{x + 1}{x - 1}) = - \frac{2}{( x - 1 ) ^{2}}

= \frac{1}{\frac{x + 1}{x - 1}} (- \frac{2}{( x - 1 ) ^{2}})

Vereinfache

\frac{1}{\frac{x + 1}{x - 1}} (- \frac{2}{( x - 1 ) ^{2}}) : - \frac{2}{( x + 1 ) ( x - 1 )}

= - \frac{2}{( x + 1 ) ( x - 1 )}

\frac{d}{d x} ((x - 2)^{4 x})

\int (tan (2 x))^{2} d x

\int_{0}^{\frac{1}{300}} 94 sin (225) d t

\int \frac{2}{t ^{3}} d t

x \to 0 lim (\frac{6 - 6 cos ( x )}{3})