What is the limit as x approaches 6 of sqrt(x^3+4x) ?

The limit as x approaches 6 of sqrt(x^3+4x) is 4sqrt(15)

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limit as x approaches 6 of sqrt(x^3+4x)

x \to 6 lim (x^{3} + 4 x)

415

Decimal

15.49193 \dots

Solution steps

x \to 6 lim (x^{3} + 4 x)

Plug in the value

x = 6

= 6^{3} + 4 \cdot 6

Simplify

6^{3} + 4 \cdot 6 : 415

= 415

\frac{d}{d x} (ln (x^{7} sin^{2} (x)))

\int \frac{1}{x ^{2} x ^{2} + a ^{2}} d x

\int x 49 - x^{2} d x

\int (2 x + \frac{3}{x ^{2}} - \frac{6}{x ^{4}}) d x

\frac{d}{d x} (sin (x) (1 + cos (x)))

What is the limit as x approaches 6 of sqrt(x^3+4x) ?
The limit as x approaches 6 of sqrt(x^3+4x) is 4sqrt(15)