What is area x(x^2-10x+30),x^2,0,5 ?

The answer to area x(x^2-10x+30),x^2,0,5 is 875/12

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area x(x^2-10x+30),x^2,0,5

area

x (x^{2} - 10 x + 30), x^{2}, 0, 5

\frac{875}{12}

Decimal

72.91666 \dots

Solution steps

Apply the area formula:

\int_{0}^{5} x (x^{2} - 10 x + 30) - x^{2} d x

Solve

\int_{0}^{5} x (x^{2} - 10 x + 30) - x^{2} d x : \frac{875}{12}

The area is:

= \frac{875}{12}

\frac{d}{d x} (\frac{- sin ( x )}{cos ( x )})

\int 6 x ln (x + 1) d x

\frac{d}{d x} (24 x)

\int \frac{1 + 2 x ^{2}}{x} d x

\int \frac{144}{x ^{3} - 12 x ^{2}} d x

What is area x(x^2-10x+30),x^2,0,5 ?
The answer to area x(x^2-10x+30),x^2,0,5 is 875/12