(\partial)/(\partial y)(4y^3-100y)

Lösung

\frac{\partial}{\partial y} (4 y^{3} - 100 y)

12 y^{2} - 100

Schritte zur Lösung

\frac{\partial}{\partial y} (4 y^{3} - 100 y)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 y^{3}) - \frac{\partial}{\partial y} (100 y)

\frac{\partial}{\partial y} (4 y^{3}) = 12 y^{2}

\frac{\partial}{\partial y} (100 y) = 100

= 12 y^{2} - 100

\int_{1}^{3} 2 4 x^{3} d x

y^{^{'}} = (1 + x) (1 + y^{2})

\int e^{(- 2 x)} d x

\int_{- 1}^{2} (y + 2) - y^{2} d y

\frac{\partial}{\partial z} (e^{c o s (x^{2})})