What is the derivative of 4cos(3x) ?

The derivative of 4cos(3x) is -12sin(3x)

What is the first derivative of 4cos(3x) ?

The first derivative of 4cos(3x) is -12sin(3x)

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\frac{d}{d x} (4 cos (3 x))

- 12 sin (3 x)

Solution steps

\frac{d}{d x} (4 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 4 (- sin (3 x) \cdot 3)

Simplify

= - 12 sin (3 x)

l a pl a ce t r an s f or m - 7 (t - 4)

\frac{d}{d x} (x (2 x + 1)^{5})

\frac{d y}{d x} = 5 y + y^{2}

t an g e n t f (x) = sin (x) + \frac{1}{2} e^{x}

\frac{d y}{d x} = \frac{3 sec ( y )}{( x + 5 ) ^{2}}

What is the derivative of 4cos(3x) ?
The derivative of 4cos(3x) is -12sin(3x)
What is the first derivative of 4cos(3x) ?
The first derivative of 4cos(3x) is -12sin(3x)